Applying basic definitions of motion, force, work and energy to some of our fundamental systems


A lot of this document can be regarded as sort of a reading comprehension exercise. 


Information from preceding assignments:

Rate of change:

Graph Trapezoids

Force, work-energy, momentum

Forces acting on objects can change their velocity, momentum and kinetic energy.

If F in the above happens to be the net force acting on an object, then the KE of that object changes by an amount equal to `dW.


As on the preceding assignment, some questions can be answered fairly directly, while others are more challenging.  Don't let yourself get bogged down on any one question before moving on to another.  Come back on another day to questions you can't answer on your first try. 

`q001.  On a graph of velocity v (in cm/sec) vs. clock time t (in sec):

`q002.  A 5 kg mass accelerates at 2 m/s^2.  What is the net force acting on the object?

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`q003.  A net force of 5000 kg m/s^2 acts on a 100 kg mass.  What is the acceleration of the mass?

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`q004.  A force of 400 Newtons is exerted on an automobile as it is pushed through a distance of 100 meters.  How much work is done on the automobile?

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`q005.  A certain pendulum requires .5 Newtons of force for every centimeter it is pulled back (recall pulling back the pendulum hanging from the tree limb, using the rubber band). 

`q006.  A system rotates through 12 rotations in 4 seconds, first coming to rest at the end of this interval.

`q007.  At the initial point of an interval a 7 kg mass is moving at 5 meters / second.  By the end of the interval it has gained an additional 200 kg m^2 / s^2 of kinetic energy. 

`q008.  An object begins an interval with a kinetic energy of 20 000 kg m^2 / s^2, and ends the interval with a kinetic energy of 15 000 kg m^2 / s^2. 

`q009.  A mass of 200 grams hangs from one side of a pulley, and another mass from the other side.  The gravitational force pulling down on this mass is about 200 000 gram cm / s^2, and the tension in the string pulling it upward is about 180 000 gram cm / s^2. 

`q010.  A pendulum of length 2 meters and mass 3 kg, pulled back a distance | x | from its equilibrium position, experiences a restoring force of magnitude k | x |, where k = 15 kg / s^2 * | x |.  [Note that for convenience in calculation we are making some approximations here; the actual value of k for this pendulum would actually be closer to 14.7 kg / s^2, and this is so only for values of | x | which are a good bit smaller than the length.  These are details we'll worry about later.]

`q011.  The force exerted on a mass has magnitude | F | = 15 Newton / meter * x, for 0 <= x <= .25 meter.

`q012.  For the rotation data you took in class:

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For University Physics Students only:

`q013.  For the v vs. t trapezoid whose width is `dt and whose altitudes are v0 and vf:

`q014.  The following allow us to define work (F * `ds), kinetic energy (1/2 m v^2), impulse (F `dt) and momentum (m v):