Problem: If the depths of water in a uniform cylinder at clock time t = 0, 10, 20, 30, and 40 seconds are 100cm., 81cm., 64cm., 49cm., 36cm., then at what average rate does the depth change during each of the corresponding 10-second intervals?
Solution: I first took the 100, (the first number in the depth sequence), And subtracted 81, (the second number in the depth sequence), from it to find the difference which is 19, (this means that the in the first interval the depth change is -19cm.). I then divided 19 by 10, (because that is the corresponding time interval), to get the average rate at which the depth changed during that time interval. Then I repeated the process for each depth interval. The rates are as follows: For the first rate is -1.9cm./sec.; the second rate is -1.7cm./sec.; the third rate is -1.5cm./sec.; and the forth and last rate is -1.3cm./sec..
Write up by:
Seth Sauer