Instructor's Answers to Questions
For example if you flip a coin 4 times, you could get 2 'heads' in 6 ways. The number 6 is in the number-4 row of Pascal's Triangle (actually the fifth row, since the first is #0) in position 2 (actually the third number since the first is in position #0).
A stochastic process is one in which you have probabilities of transitions between states, like the sane-demented model or the sane-borderline-demented model. The columns of the transition matrix represent the probabilities of the different possible transitions of one categorye.g., the first column represents the probabilities of transitions of the sane grouopand thus must add to 1.
Altitude for a trapezoidal graph is how far you are above the horizontal axis. Each trapezoid has two sides.
This question isn't specific enough to answer. Actually it's a comment, not a question.
A curve is asymptotic to a line if the curve gets closer and closer to the line, approaching to any possible degree of closeness, but never reaching the line. For example 1 / x gets smaller and smaller, without bound, but never reaches 0. So the graph of 1/x is asymptotic to the x axis.
The Christmas Tree problem is an example of a cellular automaton.
k represents a number that can have any value required by the situation. e^(.01 t) and e^(3 t) are both exponential functions, but the graph of the first is much 'flatter' than the graph of the second.
Slope is rise / run from point to point. The run is the 'horizontal' displacement from the first point to the second; the rise is the 'vertical' displacement from the first point to the second. The area of a trapezoid is the product of the average altitude and the width of the trapezoid. The trapezoid has two altitudesfrom the x axis up to the first point, and from the x axis up to the second point.
First you gotta have a function, say y = f(x) = 3 x^2 + 4 x 7, and you want to find the average rate of change between two x values. So you have to pick two x values. Say the values are x1 = 2 and x2 = 5. Then you find y1 = f(2) and y2 = f(5). Subtract to find the change in y, subtract to find the change in x, and find (change in y) / (change in x).
It's the Christmas Tree Lights problem, as worked in class last week.
C(n,r) is the number in row n at position r of Pascal's Triangle, and tells you how many of the possible outcomes of a toss of n coins will have r 'heads'.
`dt stands for delta-t with the Greek Delta. `dt is the time interval between which the values of the quadratic are calculated. If we want to find the rate of change of a function at a specific value of t, we need to find the average rate of change over smaller and smaller intervals in the vicinity of that t value. We find the average rate of change between t and t + `dt, then we see what happens at `dt shrinks to 0.
What is the question?
If you know how to find k from the given information you can use this function.
Like the magnets, and even more like the Christmas Tree Lights.
See page 5 of handout when you get it
Break it down to a specific example. If n = 10 and r = 4, what does that mean? How far do we end up from the starting point? What if n = 10 and r = 8? Where do we have to use the absolute value and why?
It's confusing but it's an importantactually essentialtopic. You are correct in your interpretation. For example if y = x(t) is the position function for an object, then v = y ' is the rate at which position changes, or the velocity, and is approximated by the slope of the trapezoidal graph. Then a = v ' = y '' is the rate at which the velocity v changes, and is called the acceleration. So a ' is the rate at which the accleration changes. You can identify with this: a car's acceleration is what makes it feel like you're pushed back in your seat. That sensation can change, and the rate at which it changes is related to the rate at which acceleration changes. Now, acceleration is the rate at which velocity changes and velocity is itself a rate. So the rate at which acceleration changes is the rate at which the rate of velocity change changes. That's a complex statement, but it can be understood.
A transition matrix has rows. They can be numbered 1, 2, 3, ..., depending on the size of the matrix. If we want to say something about what happens in any single row of the matrix we don't want to confine ourselves to row 2, or row 5, or any specific row. So we need a way to refer to a general row. So we let i stand for the number of the row. (The reason for the letter i is that it stands for 'index'the number of a row is its index).
It's what you did in the hall with the coins. The direction of each step is randomly determined by a coin flip.
Diffusion is experienced as the natural movement of things from greater concentration to lesser concentration. It's a 'spreading out' process. It generally occurs as a result of the fact that things like species concentrations in an ecosystem, chemicals in a solution, bugs on trees, and lots and lots of other things are randomly walking around, which causes them to diffuse outward from areas of high concentration.
You could find its length using the Pythagorean Theorem, and that's an important property in itself, but its main property for most applications is its slope, which is rise / run from point to point.
** If you know how fast water comes out and if you know the cross-sectional area of the stream, you can find the volume of a 1-second section of the stream, which translates immediately into the rate at which volume is being lost from the cylinder or cone. **
A cell or a lattice point is just a more formal way of referring to a 'tree'. Actually, a 'tree' is just an easy-to-understand version of a cell or a lattice point.
The matrix you get for the bug transition model is tri-diagonal: Everything is zero except for the main diagonal of the matrix and the diagonals directly above and below it.
How you do that depends on your calculator. Ask one of us.
This questions isn't specific enough.
You use those things to analyze a random walk.
right
Right
Possibilities for 2 flips: HH, HT, TH, TT.
To get possibilities for 3 flips write down the possibilities for 2 flips twice:
HH, HT, TH, TT
HH, HT, TH, TT
Then add H to the beginning of each possibility in the first row and T to the beginning of each possibility in the second:
HHH, HHT, HTH, HTT
THH, THT, TTH, TTT.
That's all that can happen for three flips.
On a regular 2-dimensional lattice bugs can travel to nearest neighbors above and below, or to the right or left.
On a circular configuration like the one on the last test bugs travel from ring to ring and then get equally distributed over each individual ring.