Time and Date Stamps (logged): 01:42:03 08-29-2008 ¯°Ÿ³±Ÿ¯²¯·Ÿ±¸Ÿ±¯¯· Applied Calculus I

Applied Calculus I Major Quiz


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Test Problems:

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Problem Number 1

Problem: Derive the expression for the instantaneous rate of change of the function y(t) = a t^2 + b t + c at clock time t.

Problem: If the rate of depth change is rate(t) = .028 t + -1.1, then what is the depth function if the depth at clock time t = 0 is 54? At what instant does the flow cease, and what is the depth at that instant?

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Problem Number 2

Problem: Write the differential equation expressing the statement that the rate which the depth y of water changes with respect to time t his proportional to the square root of the depth.

Problem: If dy / dt = 1.12 y + 1.13 / (t+1), and if at t = 0 we have y = .55, then find the approximate value of y when t = .4. Using the new values of y and t, find approximate value y when t = .8. Continue for two more steps to find the approximate value of y when t = 1.6.

(extra credit): Use a predictor-corrector method, with `Dt = .8  instead of the .5 used above, to find the approximate value of y when t = 1.6. Which value do you think is more accurate?

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Problem Number 3

If the function y = .029 t2 + -1.4 t + 88 represents depth y vs. clock time t, then what is the average rate of depth change between clock time t = 6.4 and clock time t = 12.8? What is the rate of depth change at the clock time halfway between t = 6.4 and t = 12.8?

What function represents the rate r of depth change at clock time t? What is the clock time halfway between t = 6.4 and t = 12.8, and what is the rate of depth change at this instant?

If the function r(t) = .211 t + -1.8 represents the rate at which depth is changing at clock time t, then how much depth change will there be between clock times t = 6.4 and t = 12.8?

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Problem Number 4

The Celsius temperature of a hot potato placed in a room is given by the function T = 67* 2- .0096 t + 23 , where t is clock time in seconds and T is temperature in Celsius.  

The rate at which the Celsius temperature of a hot potato placed in a room is given by Rate = .04 * 2- .0096 t, where R is rate of change in Celsius degrees per second and t is clock time in seconds.  How much temperature change do you estimate would occur between t = 14.6 and t = 29.2 seconds?

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Problem Number 5

Sketch and completely label a trapezoidal approximation graph for the function y = 2 x/ 6, for x = 0 to 2.7 by increments of .9.