Mathematical Modeling I Problems 0627


Mathematical Modeling 2001

Problems 0627

1. The rate at which water level y changes in a uniform cylinder is -.3 cm / sec * `sqrt( depth in cm), abbreviated by

dy / dt = -.3 `sqrt ( y ).

If the water level is originally y = 100 cm, then

Starting from the new level:

Starting from the new level:

Continue this process for 3 more steps.

Make a table and a graph of water level vs. clock time. What function models your results?

2. If the rate at which the temperature of your thermometer changes is given by rate = -.8 deg / sec * (difference between thermometer temperature and room temperature), abbreviated

dT / dt = -.048 ( T – Tr)

then if the initial temperature is 100 degrees and the room temperature is 50 degrees:

Starting from the initial temperature:

Starting from the new temperature:

Repeat this process for three more steps.

Make a table and a graph of temperature excess (this is the excess temperature above room temperature—i.e., subtract room temperature from actual temperature) vs. clock time and see what function models your results.

3. When a pendulum is at displacement x from its equilibrium position, the rate at which its velocity changes with respect to clock time is given by

rate of velocity change = -20 cm/s/s * displacement from equilibrium

which is abbreviated

dv / dt = -20 * x.

If the pendulum is originally 10 cm from its equilibrium position and at rest then:

Starting from the new position:

Repeat this process for three more steps.

Make a table and a graph of pendululm position vs. clock time.

4. A uniform cylinder has radius 4 cm and is initially filled to a depth of 90 cm above a hole .4 cm in diameter. Water flows through the hole at a speed given by v = `sqrt( 2 * 980 * y), where y is the depth in cm and v is the velocity in cm / sec.

Initially:

Starting from this depth:

Repeat this calculation for three more 5-second time intervals. Make a table and sketch a graph of depth vs. clock time.

5. Sketch by hand a graph of rubber band stretch vs. number of milliliters of water. Estimate the equation of the best-fit line by sketching the line that best fits the data and measuring its slope (use points on the line to measure the slope—don't use data points). Is there a pattern to the way your data differ from the straight-line prediction?

Note that stretch is the length in excess of the maximum unstretched length of the rubber band.

6. Sketch by hand a graph of range of water stream vs. of milliliters of water. Estimate the equation of the best-fit line by sketching the line that best fits the data and measuring its slope (use points on the line to measure the slope—don't use data points). Is there a pattern to the way your data differ from the straight-line prediction?

Assuming that the depth vs. clock time function is quadratic, why should we expect the flow range to be linear?

7. What depth function would go with a rate-of-depth-change function y' = dy/dt = .01 t – 3?

What rate function y' would go with a depth function y = .07 t^2 – 3 t + 12?

8. If you had two rubber bands in series—hook, rubber band, hook, rubber band—and redid the experiment, how would your graph of stretch vs. weight be changed?

If you had two rubber bands in parallel—hook, two rubber bands from that hook, then another hook attached beneath to both rubber bands—then if you redid the experiment how would your graph of stretch vs. weight be changed?